Odpowiedzi

2009-10-08T16:23:26+02:00
Dane:
m_w = 10 l = 10 kg
t_w = 10 C
t_a = 150 C
Δt_w = 1C
c_w = 4200 J/(kg*K)
c_a = 896 J/(kg*K)

szukane:
m_a = ?

ΔT_w = Δt_w = 1 K
Δt_a = t_a - (t_w + Δt_w) = 139 K
ΔT_a = Δt_a = 139 K

0 = Q_w - Q_a
Q_a = Q_w

Q_w = c_w * ΔT_w * m_w
Q_w = c_a * ΔT_a * m_a

c_w * ΔT_w * m_w = c_a * ΔT_a * m_a
m_a = (c_w * ΔT_w * m_w)/(c_a * ΔT_a)

m_a = [4200 J/(kg*K) * 1 K * 10 kg]/[896 J/(kg*K) * 139 K] = [42000 kg]/[124544] ≈ 337,23 g

m_a ≈ 337,23 g