Odpowiedzi

2009-10-07T22:41:23+02:00
M C = 12 g
m H = 1 g

etan - C2H6
mC2H6 = 2 x 12 + 6 x 1 = 30 g
mC w C2H6 = 24 g

30 g - 100%
24 g - x
x= 24 x 100 / 30 = 80%


eten - C2H4
mC2H4 = 2 x 12 + 4 x 1 = 28 g
mC w C2H4 = 2 x 12 = 24 g

28 g - 100%
24 g - x
x= 2400/28 =85,7 %


etyn - C2H2
mC2H2 = 2 x 12 + 2 x 1= 26 g
m C w C2H2 = 12 x 2 = 24 g

26g -100%
24g - x
x= 2400/26 =92 %
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