Odpowiedzi

2010-02-05T19:25:08+01:00
( x² + x - 6)(x +1) = 0
x² + x - 6 = 0
Δ = 1 -4*(-6) = 1 + 24 = 25
√Δ = √5 = 5
x1 = [-1 -5]/2 = -6/2 = -3
x2 = [-1 +5]/2 = 4/2 = 2
( x² + x - 6)(x +1) = (x +3)(x+1)(x -2) = 0
Pierwiastki tego równania to :
x1 = -3
x2 =2
x3 = -1
1 5 1