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Najlepsza Odpowiedź!
2010-02-06T13:03:13+01:00
F(0),f(-1½),f(√2),f(√3+1),f(π),f(k)

a)f(x)=2√3x

f(0) = 2√3*0 = 0
f(-1½) = 2√3*(-1½) = -3√3
f(√2) = 2√3*√2 = 2√6
f(√3+1) = 2√3*√3+1 = 2*3+1 = 7
f(π) = 2√3*π = 2√3π
f(k) = 2√3*k = 2√3k

b)f(x)= Ix-√2I

f(0) = I0-√2I = √2
f(-1½) = Ix-√2I = |-1½-√2| = 1½-√2
f(√2) = |√2-√2| = 0
f(√3+1) = |√3+1-√2| = √3+1-√2

nie wiem cy to jest dobrze, pokrecone jakies przyklady ;p