Odpowiedzi

2010-02-06T14:41:55+01:00
Al2O3= 2*27u+3*16u=102u ---m.czast. 102g/mol --- m.molowa
H3PO4=3*1u+31u+4*16u=98u 98g/mol
Fe2O3= 2*56u+3*16u=160u 160g/mol
MgCl2=24u+2*35=94u 64g/mol
CH3COOH=12u+1u*3+12u+2*16+1u=60u 60g/mol
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2010-02-06T14:47:50+01:00
Al2O3
masa cząsteczkowa:
27u*2+16u*3=54u+48u=102u
masa molowa:
M Al2O3= 2*27g/mol+3*16g/mol=102g/mol
H3PO4
masa cząsteczkowa
1u*3+ 31u+16u*4=98u
masa molowa
MH3PO4= 3*1g/mol+31g/mol+4*16g/mol=98g/mol
Fe2O3
masa cząsteczkowa
56u*2+16u*3=112u+48u=160u
masa molowa
MFe2O3=2*56g/mol+3*16g/mol=160g/mol
MgCl2
masa cząsteczkowa
24u+35,5u*2=24u+71u=95u
molowa:
24g/mol+2*35,5g/mol=95g/mol
CH3COOH
12u+1u*3+12u+16u+16u+1u=60u
molowa:
12g/mol+3*1g/mol+12g/mol+16g/mol+16g/mol+1g/mol=6-g/mol
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