Odpowiedzi

2010-02-06T20:30:39+01:00
A(3,8) B(-1,4) S(1,5)

C= A +2wektorAS
(x,y)= (3;8) + [-2;-3]
(x,y)= (-1;2)
C= (-1;2)

D= B +2wektorBS
(x,y)= (-1;4) + [2;1]
(x,y)= (3;6)
D= (3;6)

|AC|=√[(-1-3)²+(2-8)²]=√[16+36]=2√13
|BD|=√[(3+1)²+(6-4)²]=√[16+4]=2√5

|BA|=|CD|=√[(3+1)²+(6-2)²]=√[16+16]=4√2
|BC|=|AD|=√[(3-3)²+(6-8)²]=√[4]=2

Ob=|BA|+|CD|+|BC+|AD|=4+8√2
3 5 3