Odpowiedzi

2010-02-07T20:46:02+01:00
X^3+4x^2-2x-8=0
x³+4x²-2x-8=0
x²(x+4)-2(x+4) = 0
(x²-2) (x+4) = 0
(x²-2) = 0 (x+4) = 0
x² = 2 x = -4
x=√2
2010-02-07T20:48:36+01:00
X^3+4x^2-2x-8=0
x³+4x²-2x-8=0
x²(x+4)-2(x+4) = 0
(x²-2) (x+4) = 0
(x²-2) = 0 (x+4) = 0
x² = 2 x = -4
x=√2 lub x = -√2 x = -4