Odpowiedzi

2010-02-08T19:45:17+01:00
Cr(OH)3 + 3NaOH = Na3[Cr(OH)6]
Cr(OH)3 + 3Na+ OH- = 3Na+ [Cr(OH)6]<-3>
2Cr(OH)3 + 3H2SO4 = Cr2(SO4)3 + 3H2O
2Cr(OH)3 + 3H+ 3SO4<-2> = 2Cr3+ 3SO4<-2> + 3H2O