Odpowiedzi

2010-02-09T20:23:26+01:00
X2-5x+6/x2-4x+3=0
2x-5x+6/2x-4x+3=0
-7x+ 6/2x+3=0 /*2x
-14x²+6+6x=0
-14x²+6x+6=0

a= -14, b= 6, c=6
Δ= b²-4ac
Δ= 6²- 4*(-14)*6
Δ= 36+ 336
Δ= 372

x₁= (-b-√Δ): 2a
x₁= (-6-2√93) : 2*(-14)
x₁= 3/14 + √93/14

x₂= (-b+ √Δ):2a
x₂= 3/14 - √93/14