Odpowiedzi

2010-02-10T12:39:18+01:00
W=[tg(α)+1/tg(α)]sin(α)cos(α)=
[tg(α)+ctg(α)]sin(α)cos(α)=
[sin(α)/cos(α)+cos(α)/sin(α)]*sin(α)cos(α)=
sin(α)+cos(α)

ODP1
W=sin(α)+cos(α)

ewentulnie mozna zaminic na iloczyn
sin(α)+sin(90-α)=2sin(45)*cos(45+α)=
2sin(45)*sin(90-45-α)=2√2/2sin²(45-α)
ODP2
W=√2sin(45-α)

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