Odpowiedzi

2010-02-11T15:38:56+01:00
2a)3(x-3)3x-9
b5(y+z)=5y+5z
4(3z-y)=12x-4y
3(4a-c)=12a-3c
-2(7-4n)=-14+8n
b)½(4z+2)=2z+1
-⅓(6b-3)=-2b+1
0,2(x-5y)=0,2x-1y
3(⅓a+1)=1a+1
3. a)4c-(3c+2)-10c=4c-3c-10c+2=-11c+2
b)7x-8-(5x+6)=7x-5x-8+6=2x-14
c)9y-(8-3y)+16+9y-3y-8+16=6y-24
d)5x-(2-4x)+8x-7=5x-4x+8x-2-7=9x+5
3 1 3