Odpowiedzi

2010-02-12T21:24:36+01:00
Tg²α + 1 = (sin α / cos α)² + 1 = sin²α / cos²α + cos²α / cos²α = (sin²α + cos²α) / cos²α = 1 / cos²α
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2010-02-12T21:26:30+01:00
Tg²α +1 = sin²α/cos²α + cos²α/cos²α = (sin²α+ cos²α)/ cos²α

sin²α+ cos²α = 1 "trygonometryczna" , zatem tg²α +1 = 1/cos²α

Pozdro
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