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2010-02-14T20:01:35+01:00

a) Mc=12g/mol
MHCOOH=46 g/mol

46g/mol - 100%
12g/mol - x %
x%= 26,09%
b)
HCOOH+KOH ----> HCOOK + H20

7 1 7
2010-02-14T20:04:01+01:00
1.
HCOOH - kwas metanowy (mrówkowy)
%C = 12u * 100% / 46u = 26,09%

2.
HCOOH + KOH -> HCOOK + H2O
1 4 1
2010-02-14T20:54:25+01:00
M HCOOH= 46g/mol

46g/mol- 100%
12g- x

x= 12g*100%/46g
x= 26,08%

HCOOH+ KOH-> HCOOK+ H₂O
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