Odpowiedzi

2010-02-17T16:18:30+01:00
(x+1)2-(2-3)2-(x+3)2+2(x-2)(x+2)= (2x+2) + (2) -2x+6+2*(x^2-4)=
2x+4-2x+6+2x^2-8= 2x^2 + 4x +2



(2x-5)2(x-1)-(3x+1)2(x+1)-(x-1)(x2+x+1)=
4x^2 -4x-10x+10-6x^2-6x-2x-2 -3x^3+1 = -3x^3 -2x^2 -22x -7


(2x-1)3-(x+1)3+(x+2)3-(x+2)(x2-2x+4)=6x-3-3x-3+3x+6-(x^3 -2x^2+4x+2x^2-4x+8)= -x^3 +6x -8