Odpowiedzi

2010-02-18T20:10:07+01:00
R=5cm
v=πr²h=200πcm³/:π
h=200:5²
h=200:25
h=8cm = wysokość walca

pole=2πr²+2πrh=2π×5²+2π×5×8=50π+80π=130πcm²

1 5 1
2010-02-18T20:10:56+01:00
R= 5cm
V= 200pi cm ²
V= pi r ² * h
200pi= pi 25 *h /:pi
200= 25 h /: 25
h=8

2 pi r²+ pi rh=
=2 pi *5²+2 pi*5*8=
=50 pi +80 pi =130 pi cm²
2010-02-18T20:14:15+01:00
R= 5
h= ?
Pc= ?

1.Obliczamy H
V= πr²* h
h= v/πr²
h= 200π/ 5²π
h= 200π/ 25π
h= 8π

2. Obliczamy Pc

Pc= 2πr² + 2πr* h
Pc+ 2 * 25π + 2*5π *8
Pc= 50π + 80π
Pc= 130π