Odpowiedzi

2009-10-14T22:25:12+02:00
A) (8i 1/6)³÷(8 i 1/6)²× x=(1 i 1/6)²
8⅙x=(7/6)²
49/6x=49/36 /:49/6
x=⅙


b) 2⁵ * x=14²÷0,5 - 2⁶ * x
32x=196:0,5-64x
32x+64x=392
96x=392 / :96
x=4 9/392

c) (1 i 3/5)²- ( 1 i 3/5)² * x = ( 4³ ÷ 5³)¹ * x
(1,6)²-(1,6)²*x = 64/125x
2,56-2,56x = 64/125x
2,56 = 64/125x+2,56x
2,56 = 0,512x+2,56x
2,56 = 3,072x / :3,072
x=0,8(3)
16 2 16