Odpowiedzi

2010-02-19T16:24:50+01:00
Fe₂O₃
a) 2*56 + 48 = 160
160 - 100
x - 70
x = 17*160/100=112
stosunek:
112/48 = 56/24 = 28/12 = 14/6 = 7/3
FeO
b)
56+16=72
72 - 100
x - 77,8
x = 56
FeO
stosunek:
56/16 = 28/8 = 14/4 = 7/2
1 5 1