Odpowiedzi

2010-02-19T16:53:06+01:00
M ch3 oh =32g
32g -100%
12-x
x=37,5% C

32-100
16-x
x=50% tlenu

% H =100-50-35,7=12,5%
1 4 1
2010-02-19T16:57:02+01:00
CH3OH=mC+4*mH+mO=12u+4u+16u=32u


mC/mCH3OH *100%=12u/32u*100%=37,5%

4mH/mCH3OH *100%=4u/32u*100%=12,5%

mO/mCH3OH *100%=16u/32u*100%=50%
Najlepsza Odpowiedź!
2010-02-19T17:03:44+01:00