Odpowiedzi

2010-02-20T09:13:14+01:00
A) (4-2x)-(x+3)=(x-5)+(-3-x)
4-2x-x-3 = x-5-3-x
-2x-x-x+x = -5-3-4+3
-3x = -9 /: (-3)
x=3

b) (3-2x)+(3x+4)=-(3-2x)+(5x+4)
3-2x+3x+4 = -3+2x+5x+4
-2x+3x-2x-5x = -3+4-3-4
-6x = -6 / :(-6)
x= 1

c) -(x+3)-(2x-1)=(1+4x)+(3+x)
-x-3-2x+1 = 1+4x+3+x
-x-2x-4x-x = 1+3+3-1
-8x = 6 / :(-8)
x = -⁶/₈ = -¾

d) -(x+3)-(2x+8)=(-3-2x)+(2x+1)
-x-3-2x-8 = -3-2x+2x+1
-x-2x+2x-2x = -3+1+3+8
-3x = 9 / :(-3)
x = 3