Odpowiedzi

2009-10-14T20:55:12+02:00
(2x-2)(x-3)<(x-3)(x-4)
2x²-6x-2x+6 < x²-4x-3x+12
2x²-x²-6x-2x+4x+3x+6-12<0
x²-x-6<0
a=1 b=-1 c=-6
delta=1+24
delta=25
pierwiastek z delty=5

x₁=(1-5)/2
x₁=-4/2
x₁=-2

x₂=(1+5)/2
x₂=6/2
x₂=3

x∈(-2,3)