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2010-02-22T10:49:52+01:00
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dane l=400 nm=4*10^(-7)m, h=6,63*10^(-34)Js, c=3*10^8m/s,
1eV = 1,6*10^(-19)J
szukane E
E = h*f.......l=c*T.....l=c/f......f=c/l
E = h*c/l = 6,63*10^(-34)Js*3*10^8m/s / 4*10^(-7)m = 4,97*10^(-19)J = 3,1 eV

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