Odpowiedzi

2009-10-16T09:16:53+02:00
Rozwiąż rowniania
2x2-7=0 x=7/4
x(5-2x)=0 2x=0
(x-3)(2x+1)=0 x=3/2
x-3x2=0 -5x=0
x2-2x+1=0 1=0
(5x)2=0 10x=0
x2-xpierwiastekz2-1=0
x(x-4)=8 x=-4
2009-10-16T10:28:31+02:00
2x²-7=0
2x²=7 / ÷2
x²=7/2
x²=3,5

x(5-2x)=0
-2x²+5x=0
-2x(x-5/2)=0
x=0 lub x=2,5

(x-3)(2x+1)=0
2x²=x-6x-3=0
2x²-5x-3=o
Δ=b²-4ac
Δ=25-4×2×(-3)=25=24=49
√49=7
x1=5-7\4=-2\4=-2
x2=5+7\4=12\4=3

x-3x²=0
3x(x-⅓)=0
x=0 lub x=-⅓

x²-2x+1=0
Δ=b²-4ac
Δ=4-4x1x1=4-4=0
x1=-b/2a=2/2=1

(5x)²=0
25x²=0/√
25x=0/:25
x=0

x²-x√2-1=0
Δ=-2-4x1x(-1)=-2+4=2
x1=√2-√2/2=0/2=0
x2=√2=√2/2=√4/2=2/2=1

x(x-4)=8
x²-4x-8=0
Δ=16-4x1x(-8)=16+32=48
Δ=√48
x1=4-√48/2x1=4-√48\2=2-√48
x2=4+√48/2=2+√48