Czy ktos pomoze. mam takie zadanie :

oblicz:
a) 125[1/3] (jedna trzecia to potega)

6[-2] (-2 to potega)

(3/7)[-1] (3/7 to ulamek, -1 to potega)

(16/81)[1/4] (16/81 to ulamek, 1/4 to potega)

0,3[-3] (-3 to potega)

1,21[1/2] (jedna druga to potega)

b) 4[3/4] (3/4 to potega)

32[-1/5] (-1/5 to potega)

25[-1,5] (-1,5 to potega)

(64/125)[-2/3] (64/125 to ulamek, -1,5 to potega)

(0,0001)[0,75] (0,75 to potega)

(0,027)[-4/3] (-4/3 to potega)


legenda znajduje sie obok.

1

Odpowiedzi

2010-02-23T15:47:03+01:00
A) 1/125 (ulamek) do potegi 3
to 1/1953125

1/36 (ulamek)

7/3 (ulamek)

81/16 (ulamek) do potegi 4
to 43046721/65536

10/3 (ulamek) do potegi 3
to 1000/9

100/121 (ulamek) do potegi 2
to 10000/14641