Odpowiedzi

2010-02-25T11:05:23+01:00
A)
{-x+1,2y=3
{x+y=6

-x+1,2y=3
x=6-y

-(6-y)+1,2y=3
x=6-y

-6+y+1,2y=3
x=6-y

2,2y=3+6
x=6-y

2,2y=9
x=6-y

y=9*10/22
x=6-y

y=90/22
x=6-y

y=4i1/11
x=6-4i1/11

y=4i1/11
x=1i10/11


b)
{x-2y=3
{2x+y=6

x=3+2y
2(3+2y)+y=6

x=3+2y
6+4y+y=6

x=3+2y
5y=6-6

x=3+2y
5y=0

x=3+2y
y=0

x=3+2*0
y=0

x=3+0
y=0

x=3
y=0