Odpowiedzi

2010-02-25T12:09:54+01:00
F(x)= 2x+3=0 x+4=0
2x=-3/:2 x=-4
x=-3/2


3x-6=0 (x-2)=0 (x+2)=0
3x=6/:3 x=2 lub x=-2
x=2

x+3=0 x2-6x+9
x=-3 delta= b kwadrat-4ac
delta= 6 do kwadratu - 4*1*9
delta=36-36
delta=0
x1=-b/2a x1=-(-6)/2*1 x1=6/2 x1=3
2 3 2