Odpowiedzi

2010-02-26T18:19:28+01:00
A) (tg 60 - sin 30) × (cos 60 - ctg 30) =
= (√3 - 0,5) * (0,5 - √3) =
= 0,5√3 - 3 - 0,25 + 0,5√3 =
= √3 - 3,25

b) 4(ctg 45 - sin 60) × (cos 30 + tg 45) =
= 4(1 - √3/2) * (√3/2 + 1) =
= (4 - 2√3) * (√3/2 + 1) =
= 2√3 + 4 - 3 - 2√3 =
= 1

c) 2(tg 30 - sin 45) × (cos 45 - ctg 60) =
= 2(√3/3 - √2/2) * (√2/2 - √3/3) =
= 2(2√6/6-5/6) =
= (2√6-5)/3
9 2 9