Odpowiedzi

2010-02-27T18:24:59+01:00
(x-1)(x-2)(x-3)= (x^2-3x+2)(x-3)= x^3 -3x^2+2x-3x^2+9x-6=

x^3-6x^2+11x-6

w(4)=a(x^3-6x^2+11x-6)=2

a(6)=2
a=3

W(x)=3x^3 -18x^2 +33x -18


X^3 --- oznacza x do potęgi 3 :)