Odpowiedzi

2009-10-20T12:33:45+02:00
Borsuk-x
lis-y

2x=3y
2y=x+5

2x=3y
-x=5-2y

2x=3y
x=-5+2y

2(-5+2y)=3y
x=-5+2y

-10+4y=3y
x=-5+2y

y=10
x=-5+2y

y=10
x=-5+2.10

y=10
x=-5+20

y=10
x=15
2009-10-20T12:40:20+02:00
X - waga borsuka,
y - waga lisa

2x=3y
2y-5=x

2(2y-5)=3y
4y-10-3y=0
y=10

x=2y-5
x=2*10 - 5= 15

x=15kg
y=10kg
2009-10-20T13:05:24+02:00
X- waga borsuka
y-waga lisa

2x=3y
2y=x+5

x=2y-5
2x=3y

x=2y-5
2(2y-5)=3y

x=2y-5
y=10

x=15
y=10