Odpowiedzi

2010-03-02T21:31:14+01:00
4(2a-b)(2a+4b)-(3a-2b)(3b-2a)=
= 4 (4a²+8ab-2ab-4b²) - (9ab-6a²-6b²+4ab) =
= 4 (4a²+6ab-4b²) - (13ab-6a²-6b²) =
= 16a²+24ab-16b² -13ab+6a²+6b² =
= 22a²+11ab -10b²

2d²-(3c-2d)(c-d)-c(c-2d)+2d² =
=2d²-(3c²-3cd-2cd+2d²) -c²+2cd+2d²=
=2d²-(3c²-5cd+2d²)-c²+2cd+2d²=
=2d²-3c²+5cd-2d²-c²+2cd+2d² =
=2d²-4c²+7cd