Odpowiedzi

2010-03-05T20:17:13+01:00
A)

2(2π*2)+6+3+2+4+6+(2π*3)/2=8π+21+3π=11π+21

b)

2π*2+2π*2,5+2π*3+2+2*7+2*4+2*1=4π+5π+6π+2+14+8+2=15π+26
1 5 1
2010-03-05T20:42:51+01:00
A)2(2π*2)+6+3+2+4+6+(2π*3)/2
=8π+21+3π
=11π+21

B)2π*2+2π*2,5+2π*3+2+2*7+2*4+2*1
=4π+5π+6π+2+14+8+2
=15π+26
2010-03-05T22:19:50+01:00
A
2*(2π*2)+3+1+2+2+1+3+3+½(2π*3)+3+3=
=2*4π+15+½*6π+6=8π+3π+15+6=11π+21

b
2π*2+2π*2½+2π*3+4+1+4+1+7+7+2=4π+2*5π/2+6π+10+14+2=
=10π+5π+26=15π+26