Odpowiedzi

2009-10-20T22:06:01+02:00
5/x-1≥3/x+2
(x+2)*5/(x-11)(x+2)≥(x-1)*3/(x-1)(x+2)
5x+10/(x-1)(x+2)≥3x-1/(x-1)(x+2)
5x+10-3x+1/(x-1)(x+2)≥0
x≠1 x≠-2
2x+11≥0
2x≥11/2
x≥5½


1/x+1/x+1=x²-2/x²+x
(x+1)/x(x+1)+x/x(x+1)=x²-2/x(x+1)
x+1+x-x²-2/x(x+1)=0
-x²+2x-1/x(x+1)=0
b²-4ac
2²-4*(-1)*(-1)=0
x₀=b²/2a
-2/-2=1