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  • Użytkownik Zadane
2010-03-04T22:35:11+01:00
A =F / m 100 km / h = 27,7 m/s
a = 2600 N / 1300 kg = 2 m / s2
a = v / t
t = v / a = 27,7 m/s * 2 m / s2 = 55,5 s
s =1/2a * t2= 1 m / s2 * (55,5 s)2 = 3080,25 m
2010-03-04T22:45:16+01:00
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dane: m=1300kg, v=100km/h=27,778m/s, T=2600 N, vk=0
szukane: t do zatrzymania
F = ma.........F=T......a = [v-vk]/t = v/t
T = mv/t
t = mv/T = 1300kg*27,778m/s //2600 N = 13,89s = 13,9s

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