Odpowiedzi

2010-03-05T15:07:56+01:00
A = 3
b = 5
c² = 3² + 5² = 9 + 25 = 34
c = √34
sin α = b/ c = 5 / √34 = (5√34) / 34
cos α = a /c = 3 / √34 = (3√34) / 34
tg α = b/a = 5/3
ctg α = a/b = 3/5
2010-03-05T17:08:54+01:00
C= przeciwprostokątna
sina=5/c

c= √3²+5² (wszystko pod pierwiastkiem)
c = √ 9+25
c = √34
sina = 5÷√ 34

cosa = 3÷c
cosa = 3/√ 34

tga = 5÷3

ctga = 3÷5