Odpowiedzi

2010-03-05T23:51:39+01:00
(x-1)(x+3)x>0
x² + 3x - x - 3x > 0
x² - x > 0
x > 0

x(do potegi2)*(x+6)*(x-2)<=0
x² * (x² - 2x + 6x - 12) <= 0
x⁴ - 2x³ + 6x³ - 12x² <= 0
x⁴ + 4x³ - 12x² <= 0
-8x <= 0 | : (-8)
x <= 0