Odpowiedzi

2010-03-05T20:11:03+01:00
Dane:
Dane:
T₁ = 20⁰C
T₂ = 1540 °C
Cw = 460 [J/kg ×⁰C]
ρ = 7,8 [g/cm³]
Rozw.:
V = 20cm x 10cm x 5cm = 1000 [cm³]
m = ρ × V = 7,8 [g/cm³] × 1000 [cm³] = 7800 g = 7,8 kg
Q = m × Cw × ΔT
ΔT= T₂ -T₁ = 1520 °C
Q = m × Cw × ( T₂ -T₁) = 7,8 kg × 460 [J/kg ×⁰C] × 1520 °C =
= 5453760 J