Odpowiedzi

2010-03-07T10:36:15+01:00

1) 3/5 y+2/5=4*5
3y+2=20
3y=20-2\:3
y=6
2)3(y+2)=5
3y+6=5
3y=5-6\:3
y=-1/3
3)chyba cos pomylilas z =
4) y/2+1/3=7/6\*6
3y+2=7
3y=7-2
3y=5\:3
y=5/3=1 2/3
5)y+3/2-(1-y)=3,5 /*2
2y+3-2(1-y)=7
2y+3-2+2y=7
4y=7-1/:4
y=1,5