Odpowiedzi

2010-03-07T10:44:14+01:00
A)1/2•4(a+b)-1/2h(a+b)=2*(a+b)-1/2ah-1/2bh=2a+2b-1/2ah-1/2bh

b)z(x-y)-(y-x)=zx-zy-y-x
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2010-03-07T10:44:29+01:00
A)1/2•4(a+b)-1/2h(a+b)=
=2(a+b)-1/2h(a+b)=
=(a+b)(2-1/2h)

b)z(x-y)-(y-x)=z(x-y)-(-x+y)=
=z(x-y)+(x-y)=(x-y)(z+1)
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