Odpowiedzi

2010-03-07T16:44:25+01:00
[-1/2x+1] ≤ 3
-1/(2x+1) -3 ≤ 0
[-1-3(2x+1)]/(2x+1) ≤ 0
(-1-6x-3) * (2x+1) ≤ 0
(-6x-4) * (2x+1) ≤ 0
-12x² - 6x - 8x - 4 ≤ 0
12x² + 14x + 4 ≥ 0
6x² + 7x + 2 ≥ 0

Δ = 49-4*6*2 = 49-48 = 1

x₁ = -7-1/12 = -8/12 = -⅔
x₂= -7+1/12 = -6/12 = -½

x≥0 <=> x∈(-∞ ; -⅔ > suma <-½ ; ∞)

nie wiem o co Ci chodzi z tym [a]