Odpowiedzi

2009-10-22T16:31:06+02:00
•(a+b)³=a³+3a²b+3ab²+b³
•(a-b)³=a³-3a²b+3ab²-b³




(2x+1)³ =(2x)³+3(2x)²*1+3*2x*1²+1³=8x³+12x²+6x
(2-3a)³=2³-3*2²*3a+3*2*(3a)²-(3a)³=8-36a+54a²-27a³
(5+b)³=5³+3*5²*b+3*5*b²+b³=125+75b+15b²+b³
(3a+2b)³=27a³+3*9a²*2b+9a*4b²=27a³+54a²b+36ab²
(x-4y)³ = x³-12x²y+48xy²-64y³
2 5 2