Odpowiedzi

2010-03-09T14:41:49+01:00
A)
MNH3=14g/mol+3*1g/mol=17g/mol
mNH3=1,7g
więc:
17g NH3---22,4dm
1,7g NH3---x
x=2,24dm3

b) MCH4=12+4*1=16g/mol
mCH4=32g
więc:
16g CH4---22,4dm3
32g CH4---x
x=44,8dm3

c) MNO=14+16=30g/mol
mNO=4,4g
więc:
30g NO--- 22,4dm3
4,4g NO---x
x=3,3dm3