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2010-03-08T19:16:58+01:00
√3(2y + 3) - 3y(2 - √3) = 0
2√3 y + 3√3 - 6y + 3√3 y = 0
- 6y + 5√3 y = 3√3
y = 3√3/(5√3 - 6) = [3√3(5√3 + 6)]/(25*3 - 36) = [3√3(6 + 5√3)]/39 = √3(6 + 5√3)/13

2x(√2 + 1) = √2(3x - 7)
2√2 x + 2x = 3√2 x - 7√2
x(2 - √2) = - 7√2 |:√2
x(√2 - 1) = - 7
x = - 7/(√2 - 1) = - 7(√2 + 1)/(2 - 1) = - 7(√2 + 1)

2√5t - 5 = 3√5(8 - 7t) |:√5
2t - √5 = 24 - 21t
23t = 24 + √5
t = (24 + √5)/23

jak masz pytania to pisz na pw