Odpowiedzi

2010-03-08T22:32:14+01:00
A.
3y-2(y-1)=-6
3y-2y+2=-6
1y+2=-6 | -2
y=-4

b.
3(3-5y)=90-5(3y-2)
9-15y=90-15y+10
9-15y=100-15y |-15y
9=100
3 2 3
2010-03-08T22:33:51+01:00
A. 3y-2(y-1)=-6
3y-2y+2 = -6
y = -6-2
y = -8

b.3(3-5y)=90-5(3y-2)
9-15y = 90-15y+10
-15y+15y = 90+10-9
0 = 91

c. 1/4z+(2-6=2/3(2-2) w tym są chyba błędy
2 4 2