Odpowiedzi

2009-10-22T19:16:38+02:00
A) (3y-2)²-(2y-3)(2y+3)=3y²-4-4y²+6y-6y-9=-y²-13
b) (x+4)²-(x-4)²=x²+16-x²+16=32


Pozdrawiam ;D.
2009-10-22T19:19:56+02:00
A) (3y-2)²-(2y-3)(2y+3)=3y²-4-4y²+6y-6y-9=-y²-13
b) (x+4)²-(x-4)²=x²+16-x²+16=32