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  • Użytkownik Zadane
2009-10-22T21:03:04+02:00
x=-2 ; y=(1/3)

2y-(2x+y)² =2*(1/3)-(2*(-2)+(1/3))²=(2/1)*(1/3)-(-4+1/3)²=(2/3)-((-12/3)+(1/3))²=(2/3)-(-11/3)²=(2/3)-(121/9)=(6/9)-(121/9)=-115/9=-12 i 7/9
2009-10-22T21:05:11+02:00
[2y-(2x+y)]² = [2×⅓-(2×-2+⅓)]²=[⅔-(-4+⅓)]=[⅔-(-3⅔)]=4⅓