Odpowiedzi

2009-10-22T22:30:31+02:00
Dane:
m wody₁= 21kg
t₁= 10⁰C
t₂= 37⁰C
t₃= 37-10= 27⁰C
C= 4200J/kg×⁰C

Szukane:
m wody₂= ?

Q₁= Q₂
m₁×C×(t₃-t₁)= m₂×C×(t₂-t₃)
m₂= m₁×c×(t₃-t₁)/C×(t₂-t₃
[m₂]= [kg× J/kg×⁰C× ⁰C/ J/kg×⁰C× ⁰C]= [kg]
m₂= 21kg× 4200J/kg×⁰C× 17⁰C/ 4200J/kg×⁰C× 10⁰C= 35,7kg
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