Odpowiedzi

2010-03-11T17:25:46+01:00
MCuO = 64u +16u = 80u
mFe₂CO₃ = 2* 56= + 12u + 3* 16u = 172u
mNa₂CO₃ = 2* 23u + 12u + 3* 16u = 106u
mAl₂O₃ = 2* 27u + 3* 16u = 96u
mFe₂(SO₃)₃ = 2* 56u + 3 * 32u + 9* 16u = 112u + 96u + 144u = 256u