Odpowiedzi

2010-03-12T23:22:42+01:00
A) A = (3a-8, 2b+3), B = (b+4, a-1)
-(3a-8)=b+4
-(2b+3)=a-1

-3a+8=b+4
-2b-3=a-1

b=-3a+4
6a-8-3=a-1

b=-3a+4
5a=10

a=2
b=-2

A=(-2,-1), B=(2,1)

b) A = (2a+3b+2½, a/2-b/3), B = [(a-b)/2, a-b - 1⅓)]
-(2a+3b+2½)=(a-b)/2
-(a/2-b/3)=a-b - 1⅓

-2a-3b-2,5=0,5a-0,5b
-0,5a+⅓b=a-b-1⅓

2,5a+2,5b=-2,5
4,5a-4=4b

a+b=-1
b=1,125a-1

2,125a-1=-1
2,125a=0
a=0
b=-1


b) A = (-½, ⅓), B = (½,-⅓)
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