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2010-03-11T23:20:35+01:00
{√6¼⁻¹×2⁻³ + [∛216⁻¹×(-√¹₉) ⁻¹]²}⁻¹+(-1i 8/19)⁻¹={√4/25 × ⅛ + [∛1/216 × (-⅓) ⁻¹]²}⁻¹+(-27/19)⁻¹={⅖ × ⅛ + [⅙ × (-3)]²}⁻¹+(-19/27)={0,05 + [-½]²}⁻¹-19/27={0,05 + ¼}⁻¹-19/27={0,3}⁻¹-19/27=10/3-19/27=90/27-19/27=71/27=2 17/27