Odpowiedzi

2010-03-12T17:42:55+01:00
1. 2C4H9OH+ 2Na= 2NaC4H9O + H2
2C4H9OH - H2
2*22,4dm3 - 156g 156g - 2g
44,8dm3 - 156g 3,7g - x
x - 3,7g x=(2g*3,7g)/156g
x=(44,8dm3*3,7g)/156g x=0,05g
x= 165,76/156g 3,7g - 1,1dm3
x=1,1dm3 0,05g - x
x=(1,1dm3*0,05g)/3,7g
x=0,01dm3
2. CH3OH + CH5COOH=CH5COOCH3+H2O
C%=(ms*100%)/mr
ms=C%*mr/100%
ms=15%*200g/100%
ms=30g
mr=ms*100%/C%
mr=30g*100%/10%
mr=300g