Odpowiedzi

Najlepsza Odpowiedź!
2010-03-14T16:17:59+01:00
1) CH₃OH
M CH₃OH = (12 + 4 + 16) g/mol = 32 g/mol
C% = 12g/32g × 100% = 37,5g
H% = 4g/32g × 100% = 12,5g
O% = 16g/32g × 100% = 50g

2) C₃H₇OH
M C₃H₇OH = (3×12 + 8×1 + 16) g/mol = 36 + 8 + 16 = 60g/mol
C% = 36g/60g × 100% = 60g
H% = 8g/60g × 100% = 13,(3)g
O% = 16g/60g × 100% = 26,(6)g